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Script Question regarding finding and renaming a CSV file

General Tech Bugs & Fixes
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Dilpreet Kaur

User

( 7 months ago )

 

I am trying to write a script that starts off with testing for the existence of a CSV file. If it finds one, rename it to listing.txt.

This is what I have but it doesn't work.

if [ -f "*.csv" ];
   then
   cp *.csv listing.txt
fi

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Sarah Jones

User

( 7 months ago )

 

Your existing code tests for the existence of a file called *.csv (literally). This is why it does not work. It does that because the * is within double quotes.

Using [ -f *.csv ] will not work as expected if there are multiple files matching the pattern. If there are multiple files matching *.csv, the cp command will additionally not work properly, unless listing.txt is the name of a directory.

To rename the first of the files matching the filename globbing pattern *.cvs in the current directory, do this:

#!/bin/sh

set -- *.csv

while [ "$#" -gt 0 ] && [ ! -f "$1" ]; do
    shift
done

if [ -f "$1" ]; then
    mv -- "$1" listing.txt
fi

This first sets the positional parameters, $1$2, etc., the all names matching *.csv in the current directory. Then it starts looking for the first regular file, or symbolic link to a regular file, among the matched names (the code assumes that the *.csv glob may expand to directory names etc.). If a regular file, or a symbolic link to one, is found, it renames that file to listing.txt.

In the zsh shell:

mv -- *.csv(-.[1]) listing.txt

This uses a glob modifier for the *.csv globbing pattern that returns the first regular file or symbolic link that matches the pattern.

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