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Liza Sain

User

( 6 months ago )

I found this questions from past year maths competition in my country, I've tried any possible way to find it, but it is just way too hard.

If a,b,ca,b,c are distinct numbers such that a2bc=2014a2−bc=2014b2+ac=2014b2+ac=2014c2+ab=2014c2+ab=2014. Then compute a2+b2+c2a2+b2+c2

(A)40304030 (B)40284028 (C)40264026 (D)40004000 (E)20142014

Adding these three equations together

 

a2+b2+c2+ab+acbc

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